-2x^2+23x+60=0

Solution for -2x^2+23x+60=0 equation:

-2x^2+23x+60=0

a = -2; b = 23; c = +60;
Δ = b2-4ac
Δ = 232-4·(-2)·60
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1009}}{2*-2}=\frac{-23-\sqrt{1009}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1009}}{2*-2}=\frac{-23+\sqrt{1009}}{-4}
$